T-SQL InStrRev

At some point you will need a VB-like InStrRev function in T-SQL. This is a script I found somewhere, for that: 

CREATE FUNCTION dbo.InStrRev (@StringCheckIn VARCHAR(254),@StringCheckFor VARCHAR(254))

Declare @StringHere INT
Declare @SpotCount INT
Declare @LookAtChars VARCHAR(254)
Declare @LengthOfStringCheckIn INT
Declare @LengthOfStringCheckFor INT

SET @StringCheckIn = LTrim(RTrim(@StringCheckIn))
SET @StringCheckFor = LTrim(Rtrim(@StringCheckFor))
SET @LengthOfStringCheckIn = Len(@StringCheckIn)
SET @LengthOfStringCheckFor = Len(@StringCheckFor)
SET @SpotCount = @LengthOfStringCheckIn - @LengthOfStringCheckFor

WHILE @SpotCount > '1'
        SET @LookAtChars = Right(Left(@StringCheckIn,@SpotCount),@LengthOfStringCheckFor)
        IF @LookAtChars = @StringCheckFor
                SET @StringHere = @SpotCount
                SET @SpotCount = @SpotCount - 1

    RETURN @StringHere

To test the function run the following in Query Analyzer:

Declare @string1 VARCHAR(254)
Declare @string2 VARCHAR(254)
Declare @PosString INT

Set @string1 = 'This is the string we are checking for the word are from the right side of the string.'
Set @string2 = 'are'

Set @PosString = dbo.InStrRev(@string1,@string2)

Print @PosString

One Response to T-SQL InStrRev

  1. Dennis Schank says:

    A function is the best idea, but here’s another way to do it without a separate function:

    declare @find varchar(50) set @find = ‘123’
    declare @string varchar(50) set @string = ‘123 abc 123 abc’

    case when charindex(@find,@string) = 0
    then 0
    else (len(@string) + 1) – (charindex(reverse(@find),reverse(@string)) + len(@find) – 1)

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